40m^2-76m+24=0

Solution for 40m^2-76m+24=0 equation:

40m^2-76m+24=0

a = 40; b = -76; c = +24;
Δ = b2-4ac
Δ = -762-4·40·24
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-44}{2*40}=\frac{32}{80}
=2/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+44}{2*40}=\frac{120}{80}
=1+1/2
$